Question:

If 2 moles of an ideal gas at 546 K has a volume of 44.8 L, then what will be its pressure?

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Use the ideal gas law \( PV = nRT \) to calculate pressure, volume, or temperature of gases.
Updated On: Jan 27, 2026
  • 1.998 atm
  • 1.098 atm
  • 2.408 atm
  • 3.129 atm
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The Correct Option is A

Solution and Explanation

Step 1: Use the ideal gas law.
The ideal gas law is given by: \[ PV = nRT \] Where: - \( P \) is the pressure, - \( V \) is the volume, - \( n \) is the number of moles of gas, - \( R \) is the ideal gas constant (\( 0.0821 \, \text{L atm/mol K} \)), - \( T \) is the temperature in Kelvin. Given: - \( n = 2 \, \text{moles} \), - \( V = 44.8 \, \text{L} \), - \( T = 546 \, \text{K} \), - \( R = 0.0821 \, \text{L atm/mol K} \). Substitute the values into the ideal gas law: \[ P = \frac{nRT}{V} = \frac{2 \times 0.0821 \times 546}{44.8} \approx 1.998 \, \text{atm} \]
Step 2: Conclusion.
The correct answer is (A) 1.998 atm.
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