20
The sequence given is a series of products of consecutive odd numbers taken three at a time. The general term for the sequence can be expressed as \( (2k-1)(2k+1)(2k+3) \), where \( k \) is the term number starting from 1. To find \( f(2) \), consider the sum of the first two terms of the series: \[ 1\cdot3\cdot5 + 3\cdot5\cdot7 = 15 + 105 = 120 \] Given that this sum is expressed by the formula \( n(n+1)f(n) \) for \( n = 2 \), we have: \[ 2(2+1)f(2) = 120 \quad \Rightarrow \quad 6f(2) = 120 \quad \Rightarrow \quad f(2) = 20 \] Thus, \( f(2) = 20 \), which confirms the correct answer as option (4).
Given the function:
\[ f(x) = \frac{2x - 3}{3x - 2} \]
and if \( f_n(x) = (f \circ f \circ \ldots \circ f)(x) \) is applied \( n \) times, find \( f_{32}(x) \).
For \( n \in \mathbb{N} \), the largest positive integer that divides \( 81^n + 20n - 1 \) is \( k \). If \( S \) is the sum of all positive divisors of \( k \), then find \( S - k \).
{If \(f(x)\) is a quadratic function such that \(f\left(\frac{1}{x}\right) = f(x) + f\left(\frac{1}{1-x}\right)\), then \(\sqrt{f\left(\frac{2}{3}\right) + f\left(\frac{3}{2}\right)} =\)}
If \[ \int e^x (x^3 + x^2 - x + 4) \, dx = e^x f(x) + C, \] then \( f(1) \) is:
In Bohr model of hydrogen atom, if the difference between the radii of \( n^{th} \) and\( (n+1)^{th} \)orbits is equal to the radius of the \( (n-1)^{th} \) orbit, then the value of \( n \) is: