Question

If 0 \(<\) p \(<\) I, which of the following has the least value? 

• A. \(\frac{1}{p^2+1}\)
• B. \(\frac{1}{\sqrt 9}\)
• C. \(\frac{1}{p^2}\)
• D. \(\frac{1}{(p+1)^2}\)

Answer 1

The Correct Option is D

A. \(\frac{1}{p^2+1}.........\frac{1}{1.0016}\)
D. \(\frac{1}{(p+1)^2}=\frac{1}{1.0016^2}\)

Only A and D are \(<1\) , and D has a larger denominator and same numerator, so D is the least.
The correct option is (D): \(\frac{1}{(p+1)^2}\)