The reaction is a chlorination reaction where benzene reacts with chlorine (\( \text{Cl}_2 \)) in the presence of anhydrous aluminium chloride (\( \text{AlCl}_3 \)), which acts as a catalyst. Since excess chlorine is used and the reaction occurs in the dark and cold, the process results in the substitution of chlorine atoms on the benzene ring. The result is the formation of hexachlorocyclohexane, or \( \text{C}_6\text{H}_3\text{Cl}_3 \), where three chlorine atoms are substituted onto the benzene ring, making the structure a trichlorobenzene. Thus, the correct product is \( \text{C}_6\text{H}_3\text{Cl}_3 \), which corresponds to option (C).
(b.)Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).