The given reaction is an example of the Hell-Volhard-Zelinsky (HVZ) reaction, which selectively brominates the $\alpha$-carbon of carboxylic acids in the presence of Br$_2$ and red phosphorus. The reaction mechanism involves the formation of an $\alpha$-brominated carboxylic acid.
\[\text{COOH} \xrightarrow{\text{Br}_2/\text{Red P}} \text{COOH-Br} \xrightarrow{\text{H}_2\text{O}} \text{COOH-Br (Product)}\]
Thus, the product formed is the $\alpha$-bromo derivative of the given carboxylic acid.
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)