The problem asks us to identify a pair of molecules, where one molecule has an odd number of electrons (a free radical), and the other has an expanded octet.
Let's examine the given options:
- Option A: BeCl₂ & HNO₃ - BeCl₂ has no unpaired electrons (Be is in Group 2 and typically forms stable molecules with paired electrons). - HNO₃ is a stable molecule with no free radicals and does not have an expanded octet. Hence, this pair doesn't satisfy the given conditions.
- Option B: NO & PF₅ - NO (Nitric oxide) is a free radical with an odd number of electrons, specifically one unpaired electron. - PF₅ (Phosphorus pentafluoride) has an expanded octet. Phosphorus can accommodate more than 8 electrons because it is in Period 3 and can use d-orbitals for bonding. This option satisfies the condition of one molecule with an odd electron and the other with an expanded octet.
- Option C: BCl₃ & NO₂ - BCl₃ has no free radicals and follows the octet rule (boron typically forms 3 bonds with no lone pairs). - NO₂ is a molecule with an odd electron (it has one unpaired electron and is a free radical). However, it does not have an expanded octet. Thus, this option doesn't fit the required condition.
- Option D: SCl₂ & NH₃ - SCl₂ follows the octet rule and has no free radicals. - NH₃ (Ammonia) follows the octet rule and also has no free radicals. Hence, this option does not meet the criteria. Therefore, the correct pair is NO & PF₅, which fits the condition of one molecule having an odd electron and the other having an expanded octet.
What is the empirical formula of a compound containing 40% sulfur and 60% oxygen by mass?
Given below are two statements :
Statement I : Wet cotton clothes made of cellulose based carbohydrate takes comparatively longer time to get dried than wet nylon polymer based clothes.
Statement II : Intermolecular hydrogen bonding with water molecule is more in nylon-based clothes than in the case of cotton clothes.
In the light of the above statements, choose the Correct answer from the options given below
Match the LIST-I with LIST-II
LIST-I | LIST-II |
---|---|
A. PF5 | I. dsp2 |
B. SF6 | II. sp3d |
C. Ni(CO)4 | III. sp3d2 |
D. [PtCl4]2- | IV. sp3 |
Choose the correct answer from the options given below:
Two point charges M and N having charges +q and -q respectively are placed at a distance apart. Force acting between them is F. If 30% of charge of N is transferred to M, then the force between the charges becomes:
If the ratio of lengths, radii and Young's Moduli of steel and brass wires in the figure are $ a $, $ b $, and $ c $ respectively, then the corresponding ratio of increase in their lengths would be: