Question:

Identify the pair of elements in which the number of electrons in the (n-1) shell is the same:

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Transition elements have their valence electrons in the \( (n) \) shell, while their \( (n-1) \) shell contains the d-electrons. When comparing elements, focus on the d-orbital occupancy to determine similarities in the \( (n-1) \) shell.
Updated On: Mar 25, 2025
  • Fe, Mn
     

  • Zn, Fe 
     

  • K, Sc 
     

  • Mn, Cr
     

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The Correct Option is D

Solution and Explanation

In this problem, we need to identify the pair of elements that have the same number of electrons in the (n-1) shell, where n represents the principal quantum number.

We need to check the electron configurations of each pair of elements and compare the number of electrons in the (n-1) shell:

1. Fe and Mn:

Electron configuration of Fe: [Ar] 3d6 4s2

Electron configuration of Mn: [Ar] 3d5 4s2

The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.

2. Zn and Fe:

Electron configuration of Zn: [Ar] 3d10 4s2

Electron configuration of Fe: [Ar] 3d6 4s2

The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.

3. K and Sc:

Electron configuration of K: [Ne] 3s2 3p6 4s1

Electron configuration of Sc: [Ar] 3d1 4s2

The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.

4. Mn and Cr:

Electron configuration of Mn: [Ar] 3d5 4s2

Electron configuration of Cr: [Ar] 3d5 4s1

Both elements have the same number of electrons (5 electrons) in the (n-1) shell, so this is the correct answer.

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