Fe, Mn
Zn, Fe
K, Sc
Mn, Cr
To determine which pair of elements has the same number of electrons in the (n-1) shell, we need to analyze the electron configurations of the elements:
The (n-1) shell for the elements given is the 3rd shell, which corresponds to the 3d subshell. Let's analyze these configurations to find pairs with the same number of electrons in this shell:
We find that both Manganese (Mn) and Chromium (Cr) have 5 electrons in the 3d subshell.
Thus, the correct pair with the same number of electrons in the (n-1) shell is Mn, Cr.
In this problem, we need to identify the pair of elements that have the same number of electrons in the (n-1) shell, where n represents the principal quantum number.
We need to check the electron configurations of each pair of elements and compare the number of electrons in the (n-1) shell:
Electron configuration of Fe: [Ar] 3d6 4s2
Electron configuration of Mn: [Ar] 3d5 4s2
The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.
Electron configuration of Zn: [Ar] 3d10 4s2
Electron configuration of Fe: [Ar] 3d6 4s2
The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.
Electron configuration of K: [Ne] 3s2 3p6 4s1
Electron configuration of Sc: [Ar] 3d1 4s2
The number of electrons in the (n-1) shell is different for both elements, so this is not the correct answer.
Electron configuration of Mn: [Ar] 3d5 4s2
Electron configuration of Cr: [Ar] 3d5 4s1
Both elements have the same number of electrons (5 electrons) in the (n-1) shell, so this is the correct answer.
The range of the real valued function \( f(x) =\) \(\sin^{-1} \left( \frac{1 + x^2}{2x} \right)\) \(+ \cos^{-1} \left( \frac{2x}{1 + x^2} \right)\) is:
If \(3A = \begin{bmatrix} 1 & 2 & 2 \\[0.3em] 2 & 1 & -2 \\[0.3em] a & 2 & b \end{bmatrix}\) and \(AA^T = I\), then\(\frac{a}{b} + \frac{b}{a} =\):
\(\begin{vmatrix} a+b+2c & a & b \\[0.3em] c & b+c+2c & b \\[0.3em] c & a & c+a2b \end{vmatrix}\)