Question:

Identify the INCORRECT statements from the following:
A. Notation $^{24_{12}Mg$ represents 24 protons and 12 neutrons.
B. Wavelength of a radiation of frequency $4.5 \times 10^{15} s^{-1}$ is $6.7 \times 10^{-8} m$.
C. One radiation has wavelength $\lambda_1$ (900 nm) and energy $E_1$. Other radiation has wavelength $\lambda_2$ (300 nm) and energy $E_2$. $E_1 : E_2 = 3 : 1$.
D. Number of photons of light of wavelength 2000 pm that provides 1 J of energy is $1.006 \times 10^{16}$.}

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Remember the relationships between Z, A, protons, and neutrons. Energy and wavelength are inversely related for photons.
Updated On: Feb 5, 2026
  • A and D Only
  • A and C Only
  • A and B Only
  • B and C Only
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The Correct Option is B

Solution and Explanation

A. The nucleus $^{24}_{12}Mg$ has $Z=12$ protons and $A-Z = 24-12 = 12$ neutrons.
The statement says 24 protons and 12 neutrons. Incorrect.
B. $\lambda = c/\nu = \frac{3 \times 10^8}{4.5 \times 10^{15}} = 0.666 \times 10^{-7} \text{ m} = 6.67 \times 10^{-8} \text{ m}$.
The statement says $6.7 \times 10^{-8} \text{ m}$. Correct.
C. Energy $E \propto 1/\lambda$. $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1} = \frac{300 \text{ nm}}{900 \text{ nm}} = \frac{1}{3}$.
The statement says $3:1$. Incorrect.
D. $N = \frac{E \lambda}{hc} = \frac{1 \times 2000 \times 10^{-12}}{(6.626 \times 10^{-34})(3 \times 10^8)} \approx 1.006 \times 10^{16}$. Correct.
The INCORRECT statements are A and C.
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