The circuit shown is a Sallen-Key filter topology. It uses an operational amplifier (op-amp) and two RC sections.
The presence of two capacitors (and two resistors in the filter network) indicates that it is a second-order filter. Each RC section contributes one pole to the filter's transfer function.
The configuration of the resistors and capacitors (series R, shunt C, then series R, shunt C to the non-inverting input of the op-amp) is characteristic of a low-pass filter. At low frequencies, capacitors act as open circuits, allowing the signal to pass. At high frequencies, capacitors act as short circuits, attenuating the signal.
The op-amp is typically configured as a voltage follower (gain = 1) or a non-inverting amplifier with a specific gain to shape the filter response (e.g., Butterworth, Chebyshev). The feedback resistors \( R_1, R_1 \) shown are likely part of a non-inverting amplifier configuration, setting a gain of \( 1 + \frac{R_1}{R_1} = 2 \) if connected from output to inverting input and from inverting input to ground respectively. However, if the output \( V_o \) is directly connected to the inverting input, it's a voltage follower.
Regardless of the exact op-amp gain configuration, the RC network determines the filter type and order. This is a second-order low-pass filter.
\[ \boxed{\text{Second order Low pass filter}} \]
A controller \( (1 + K_{DS}) \) is to be designed for the plant \[ G(s) = \frac{1000 \sqrt{2}}{s(s + 10)^2} \] The value of \( K_D \) that yields a phase margin of 45 degrees at the gain cross-over frequency of 10 rad/sec is ……… (round off to 1 decimal place).
Consider the state-space model:
\[ \dot{x}(t) = A x(t) + B u(t) \] \[ y(t) = C x(t) \] \[ A = \begin{bmatrix} 0 & 1 \\ -2 & -3 \end{bmatrix}, \quad B = \begin{bmatrix} 0 \\ 1 \end{bmatrix}, \quad C = \begin{bmatrix} 1 & 0 \end{bmatrix} \]The sum of the magnitudes of the poles is: