Identify the correct statements from the following:
For an ideal gas, the compressibility factor is 1.0.
The kinetic energy of NO (g) (molar mass = 30 g mol-1) at T(K) is \( x \) J mol-1. The kinetic energy of N2O4 (g) (molar mass = 92 g mol-1) at T(K) is \( 2x \) J mol-1.
The rate of diffusion of a gas is inversely proportional to the square root of its density.
Step 1: Let's evaluate each statement.
Statement I: For an ideal gas, the compressibility factor \( Z \) is defined as: \[ Z = \frac{P V_m}{R T} \] For an ideal gas, this value is 1.0, so Statement I is true.
Step 2: Now consider Statement II. The kinetic energy \( E_k \) of a gas molecule is given by: \[ E_k = \frac{3}{2} R T \] The kinetic energy is directly proportional to temperature for a given substance. The relationship given in the question, where the kinetic energy of N_2O_4 is twice that of NO at the same temperature, is consistent with this law. So Statement II is also true.
Step 3: Statement III states that the rate of diffusion of a gas is inversely proportional to the square root of its density. This is a correct statement according to Graham's law of diffusion: \[ \text{Rate of diffusion} \propto \frac{1}{\sqrt{\text{Density}}} \] Thus, Statement III is also true.
Step 4: All statements I, II, and III are true. Therefore, the correct answer is option (3), which includes statements I and III.
The rate of a reaction:
A + B −→ product
is given below as a function of different initial concentrations of A and B.
Experiment | \([A]\) (mol L\(^{-1}\)) | \([B]\) (mol L\(^{-1}\)) | Initial Rate (mol L\(^{-1}\) min\(^{-1}\)) |
---|---|---|---|
1 | 0.01 | 0.01 | \(5 \times 10^{-3}\) |
2 | 0.02 | 0.01 | \(1 \times 10^{-2}\) |
3 | 0.01 | 0.02 | \(5 \times 10^{-3}\) |
The percentage error in the measurement of mass and velocity are 3% and 4% respectively. The percentage error in the measurement of kinetic energy is: