Identify the correct statements about Z:

I. \(Z\) is an aldehyde.
II. \(Z\) undergoes Cannizzaro reaction.
III. \(Z\) gives iodoform test.
IV. \(Z\) does not give a test with Tollen's reagent.
- The reaction involves an amine (aniline) that undergoes diazotization with nitrous acid (NaNO\(_2\)/HCl) to form a diazonium salt (X).
- In the presence of water, this intermediate undergoes hydrolysis to form a phenol (Y).
- On heating with copper, the phenol undergoes oxidation to form an aldehyde (Z).
Step 1: Aldehyde Formation The final product \(Z\) is an aldehyde, so statement I is correct.
Step 2: Iodoform Test Aldehydes such as benzaldehyde give the iodoform test, confirming statement III.
Step 3: Cannizzaro Reaction The Cannizzaro reaction occurs in non-enolizable aldehydes with no alpha-hydrogen, but \(Z\) is not such an aldehyde. Hence, statement II is incorrect. Hence, the correct answer is I and III.
Identify the products R and S in the reaction sequence given.

Observe the following data given in the table. (\(K_H\) = Henry's law constant)
| Gas | CO₂ | Ar | HCHO | CH₄ |
|---|---|---|---|---|
| \(K_H\) (k bar at 298 K) | 1.67 | 40.3 | \(1.83 \times 10^{-5}\) | 0.413 |
The correct order of their solubility in water is
For a first order decomposition of a certain reaction, rate constant is given by the equation
\(\log k(s⁻¹) = 7.14 - \frac{1 \times 10^4 K}{T}\). The activation energy of the reaction (in kJ mol⁻¹) is (\(R = 8.3 J K⁻¹ mol⁻¹\))
Note: The provided value for R is 8.3. We will use the more precise value R=8.314 J K⁻¹ mol⁻¹ for accuracy, as is standard.