To determine the correct statements about p-block elements and their compounds, we need to evaluate each statement based on our understanding of chemistry:
Thus, the correct statements are (A) and (C). Hence, the correct answer is the option:
(A) and (C) only
Statement (A): True.Non-metals, being more electronegative, tend to attract electrons more strongly compared to metals.
Statement (B): False. Non-metals generally have higher ionization enthalpy than metals due to their smaller atomic sizes and higher nuclear charges.
Statement (C): True. Compounds formed between highly reactive metals (like alkali metals) and highly reactive non-metals (like halogens) are ionic in nature due to significant electronegativity differences.
Statement (D): False. Non-metal oxides are generally acidic in nature, not basic
Statement (E): False. Metal oxides are generally basic in nature, though some transition metal oxides may be amphoteric or acidic.
Thus, the correct statements are:
\[\text{(A) and (C) only.}\]
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: