Identify the correct statements about group 14 elements:
I. Sn in +2 state is a reducing agent and Pb in +4 state is a strong oxidising agent.
II. Thermodynamically most stable allotrope of carbon is diamond.
III. SiCl\(_4\) on hydrolysis gives silicic acid.
IV. Sn has a higher melting point than Pb.
Statement I: Correct. \( \text{Sn}^{2+} \) acts as a reducing agent, whereas \( \text{Pb}^{4+} \) is a strong oxidizing agent due to the inert pair effect.
Statement II: Incorrect. The thermodynamically most stable allotrope of carbon is graphite, not diamond.
Statement III: Correct. \( \text{SiCl}_4 \) reacts with water to form silicic acid \( \text{H}_4\text{SiO}_4 \).
Statement IV: Incorrect. Lead (Pb) has a higher melting point than tin (Sn), making this statement false.
Thus, the correct answer is I, III only.
To solve the problem, we need to identify the correct statements about Group 14 elements.
1. Understanding the Statements:
Let's go through the statements one by one:
Statement I: "Sn in +2 state is a reducing agent and Pb in +4 state is a strong oxidising agent." This statement is correct because tin (Sn) in the +2 oxidation state is a reducing agent, and lead (Pb) in the +4 oxidation state is a strong oxidizing agent.
Statement II: "Thermodynamically most stable allotrope of carbon is diamond." This statement is incorrect. The most thermodynamically stable allotrope of carbon at room temperature is graphite, not diamond.
Statement III: "SiCl₄ on hydrolysis gives silicic acid." This statement is correct. Silicon tetrachloride (SiCl₄) reacts with water (hydrolyzes) to form silicic acid.
Statement IV: "Sn has higher melting point than Pb." This statement is incorrect. Lead (Pb) has a higher melting point than tin (Sn). The melting point of Sn is 231.9°C, while Pb has a melting point of 327.5°C.
Final Answer:
The correct answer is Option A: I, III only.
Find the least horizontal force \( P \) to start motion of any part of the system of three blocks resting upon one another as shown in the figure. The weights of blocks are \( A = 300 \, {N}, B = 100 \, {N}, C = 200 \, {N} \). The coefficient of friction between \( A \) and \( C \) is 0.3, between \( B \) and \( C \) is 0.2 and between \( C \) and the ground is 0.1.