Question:

Identify the correct statements about group 14 elements: 
I. Sn in +2 state is a reducing agent and Pb in +4 state is a strong oxidising agent. 
II. Thermodynamically most stable allotrope of carbon is diamond. 
III. SiCl\(_4\) on hydrolysis gives silicic acid. 
IV. Sn has a higher melting point than Pb.

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Reviewing thermodynamic stability and common chemical reactions helps in understanding and predicting the behavior of elements, especially within the same group of the periodic table.
Updated On: Apr 15, 2025
  • I, III only
  • II, III only
  • I, IV only
  • II, IV only
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The Correct Option is A

Approach Solution - 1

Step 1: Evaluating each statement.

Statement I: Correct. \( \text{Sn}^{2+} \) acts as a reducing agent, whereas \( \text{Pb}^{4+} \) is a strong oxidizing agent due to the inert pair effect.

Statement II: Incorrect. The thermodynamically most stable allotrope of carbon is graphite, not diamond.

Statement III: Correct. \( \text{SiCl}_4 \) reacts with water to form silicic acid \( \text{H}_4\text{SiO}_4 \).

Statement IV: Incorrect. Lead (Pb) has a higher melting point than tin (Sn), making this statement false.

Thus, the correct answer is I, III only.

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Approach Solution -2

To solve the problem, we need to identify the correct statements about Group 14 elements.

1. Understanding the Statements:
Let's go through the statements one by one:

Statement I: "Sn in +2 state is a reducing agent and Pb in +4 state is a strong oxidising agent." This statement is correct because tin (Sn) in the +2 oxidation state is a reducing agent, and lead (Pb) in the +4 oxidation state is a strong oxidizing agent.

Statement II: "Thermodynamically most stable allotrope of carbon is diamond." This statement is incorrect. The most thermodynamically stable allotrope of carbon at room temperature is graphite, not diamond.

Statement III: "SiCl₄ on hydrolysis gives silicic acid." This statement is correct. Silicon tetrachloride (SiCl₄) reacts with water (hydrolyzes) to form silicic acid.

Statement IV: "Sn has higher melting point than Pb." This statement is incorrect. Lead (Pb) has a higher melting point than tin (Sn). The melting point of Sn is 231.9°C, while Pb has a melting point of 327.5°C.

Final Answer:
The correct answer is Option A: I, III only.

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