The given sequence involves the following steps:
Step 1: Friedel-Crafts Acylation
Benzene (\(\text{C}_6\text{H}_6\)) reacts with acetyl chloride (\(\text{CH}_3\text{COCl}\)) in the presence of \(\text{AlCl}_3\), an electrophilic catalyst. This forms acetophenone (\(\text{C}_6\text{H}_5\text{COCH}_3\)) as compound \(A\):
\[\text{C}_6\text{H}_6 + \text{CH}_3\text{COCl} \xrightarrow[\text{AlCl}_3]{} \text{C}_6\text{H}_5\text{COCH}_3 \, (A).\]
Step 2: Clemmensen Reduction
Acetophenone (\(\text{C}_6\text{H}_5\text{COCH}_3\)) undergoes Clemmensen reduction using zinc amalgam (\(\text{Zn–Hg}\)) and hydrochloric acid (\(\text{HCl}\)). The carbonyl group (\(-\text{CO}\)) is reduced to a methylene group (\(-\text{CH}_2-\)), resulting in ethylbenzene (\(\text{C}_6\text{H}_5\text{CH}_2\text{CH}_3\)) as compound \(B\):
\[\text{C}_6\text{H}_5\text{COCH}_3 \xrightarrow[\text{Zn–Hg, HCl}]{} \text{C}_6\text{H}_5\text{CH}_2\text{CH}_3 \, (B).\]
Step 3: Acidic Oxidation
Ethylbenzene reacts with \(\text{H}^+\) under oxidation conditions to form acetophenone again. This completes the reaction cycle.
Final Products:
\(A = \text{C}_6\text{H}_5\text{COCH}_3\) (Acetophenone).
\(B = \text{C}_6\text{H}_5\text{CH}_2\text{CH}_3\) (Ethylbenzene).
Conclusion: The correct identification of \(A\) and \(B\) is given in option \((3)\).
Final Answer: (3).
Consider the gas phase reaction: \[ CO + \frac{1}{2} O_2 \rightleftharpoons CO_2 \] At equilibrium for a particular temperature, the partial pressures of \( CO \), \( O_2 \), and \( CO_2 \) are found to be \( 10^{-6} \, {atm} \), \( 10^{-6} \, {atm} \), and \( 16 \, {atm} \), respectively. The equilibrium constant for the reaction is ......... \( \times 10^{10} \) (rounded off to one decimal place).
Molten steel at 1900 K having dissolved hydrogen needs to be vacuum degassed. The equilibrium partial pressure of hydrogen to be maintained to achieve 1 ppm (mass basis) of dissolved hydrogen is ......... Torr (rounded off to two decimal places). Given: For the hydrogen dissolution reaction in molten steel \( \left( \frac{1}{2} {H}_2(g) = [{H}] \right) \), the equilibrium constant (expressed in terms of ppm of dissolved H) is: \[ \log_{10} K_{eq} = \frac{1900}{T} + 2.4 \] 1 atm = 760 Torr.