The correct option is(A): 0.917.
When the density of an object is less than the density of the fluid it's placed in (in this case, the iceberg's density is less than the density of water), it will float. The fraction submerged will be equal to the ratio of their densities, which is 0.917 in this case. This means 91.7% of the iceberg's volume is submerged in the water.
Let \(V\) be the total volume of the iceberg and \(V'\) of its volume be submerged into water
Floatation condition weight of iceberg = Weight of water displaced by submerged part by ice
\(V \rho_{i} g=V' \rho_{w} g\)
\(\Rightarrow V' / V=\rho_{i} / \rho_{w}\)
\(=0.917 / 1=0.917\)
When an iceberg floats in water, the fraction of the iceberg submerged can be found by comparing the density of the iceberg to the density of water. The fraction submerged is given by: \[ \text{Fraction submerged} = \frac{\rho_{\text{ice}}}{\rho_{\text{water}}} \] Given that the density of ice (\(\rho_{\text{ice}}\)) is 0.917 g/cm\(^3\) and the density of water (\(\rho_{\text{water}}\)) is 1.0 g/cm\(^3\), we can calculate the submerged fraction: \[ \text{Fraction submerged} = \frac{0.917}{1.0} = 0.917 \] Thus, the correct answer is (A) 0.917.
When an iceberg floats on water, it displaces a volume of water equal to the weight of the iceberg. According to Archimedes' principle, the fraction of the iceberg submerged is given by the ratio of the density of ice to the density of water. Let the density of ice be \( \rho_i \) and the density of water be \( \rho_w \). The fraction of the volume of the iceberg submerged is: \[ \text{Fraction submerged} = \frac{\rho_i}{\rho_w} \] The density of water \( \rho_w \) is approximately \( 1.00 \, \text{g/cm}^3 \), and the density of ice is given as \( \rho_i = 0.917 \, \text{g/cm}^3 \). Substituting the values: \[ \text{Fraction submerged} = \frac{0.917}{1} = 0.917 \] Thus, the fraction of the iceberg submerged is \( 0.917 \).
For an application where the Reynolds number is to be kept constant, a liquid with a density of 1 g cm\(^-3\) and viscosity of 0.01 Poise results in a characteristic speed of 1 cm s\(^-1\). If this liquid is replaced by another with a density of 1.25 g cm\(^-3\) and viscosity of 0.015 Poise, the characteristic velocity will be ......... cm s\(^-1\) (rounded off to one decimal place).
Consider a fully developed, steady, one-dimensional, laminar flow of a Newtonian liquid through a pipe. The maximum velocity in the pipe is proportional to which of the following quantities?
Given: \( \Delta P \) is the difference between the outlet and inlet pressure, \( \mu \) is the dynamic viscosity of the liquid, and \( R \) and \( L \) are the radius and length of the pipe, respectively.
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly:
A horizontal force of 0.5 N is required to move a metal plate of area \( 10^{-2} \, {m}^2 \) with a velocity of \( 3 \times 10^{-2} \, {m/s} \), when it rests on \( 0.5 \times 10^{-3} \, {m} \) thick layer of glycerin. Find the viscosity of glycerin.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
Viscosity is a measure of a fluid’s resistance to flow. The SI unit of viscosity is poiseiulle (PI). Its other units are newton-second per square metre (N s m-2) or pascal-second (Pa s.) The dimensional formula of viscosity is [ML-1T-1].
Viscosity is measured in terms of a ratio of shearing stress to the velocity gradient in a fluid. If a sphere is dropped into a fluid, the viscosity can be determined using the following formula:
η = [2ga2(Δρ)] / 9v
Where ∆ρ is the density difference between fluid and sphere tested, a is the radius of the sphere, g is the acceleration due to gravity and v is the velocity of the sphere.