Question:
I=\(∫^{\frac{π}{3}} _{\frac{π}{6} }\frac{dx}{1+√cot x}\), then I=
I=\(∫^{\frac{π}{3}} _{\frac{π}{6} }\frac{dx}{1+√cot x}\), then I=
Updated On: Oct 7, 2024
- \(\frac{π}{12}\)
- \(\frac{π}{16}\)
- \(\frac{π}{2}\)
- \(\frac{π}{8}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{π}{12}\)
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