Question

Hybridization of $\mathrm{Fe}$ in ${\mathrm{K}}_3[\mathrm{Fe}(\mathrm{CN}{)}_6]$ is:

• (A) ${\mathrm{sp}}^3$
• (B) $d^{2}s{p}^3$
• (C) ${\mathrm{sp}}^3{\mathrm{d}}^2$
• (D) $ds{p}^3$

Answer 1

The Correct Option is B

Explanation:
Hybridization of $\mathrm{Fe}$ in ${\mathrm{K}}_3[\mathrm{Fe}(\mathrm{CN}{)}_6]$ is $d^{2}s{p}^3$.In the given complex of ${\mathrm{Fe}}^{3+}$, as the co-ordination number is ' 6 ', there are two possibilities. It can be $d^{2}s{p}^3$ or $s{p}^3{d}^2$. But the ligand attached with central metal ion, ${\mathrm{Fe}}^{3+}$, is strong field ligand so it willpromate inner orbital complex, $d^{2}s{p}^3$.Hence, the correct option is (B).