How will you convert:
(i) Ethanoic acid into methanamine
(ii) Hexanenitrile into 1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine into methanamine
(v) Ethanoic acid into propanoic acid
(vi) Methanamine into ethanamine
(vii) Nitromethane into dimethylamine
(viii) Propanoic acid into ethanoic acid?
How will you convert:
(i) Ethanoic acid into methanamine
(ii) Hexanenitrile into 1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine into methanamine
(v) Ethanoic acid into propanoic acid
(vi) Methanamine into ethanamine
(vii) Nitromethane into dimethylamine
(viii) Propanoic acid into ethanoic acid?
Solution and Explanation
Top Questions on Amines
- An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br₂ and KOH forms compound (R) having molecular formula C₆H₇N. Names of P, Q and R respectively are.
- Benzene undergoes the following sequence of reactions:
- Statement-I : $\text{KMnO}_4 \xrightarrow{\Delta} \text{NH}_2$ followed by $\text{Br}_2/\text{KOH} \rightarrow \text{NH}_2$.
Statement-II : $\text{CH}_3\text{NH}_2 \xrightarrow{(i) \text{ Br}_2/\text{H}_2\text{O}, (ii) \text{ NaNO}_2/\text{HCl}, (iii) \text{ H}_3\text{PO}_2/\Delta} \text{CH}_3\text{Br}$. - Which of the following reaction is correctly matched with their product ?
- Observe the following reaction sequence:
\text{(P) }\xrightarrow{\text{NH}_3, \Delta} \text{(Q)} \xrightarrow{\text{Br}_2, \text{KOH}} \text{(R)}
Which of the following is the correct structure for P, Q, and R?
Questions Asked in CBSE CLASS XII exam
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Reason (R): The half-life of a reaction does not depend upon the initial concentration of the reactant in a first order reaction.- CBSE CLASS XII - 2025
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Rishika and Shivika were partners in a firm sharing profits and losses in the ratio of 3 : 2. Their Balance Sheet as at 31st March, 2024 stood as follows:
Balance Sheet of Rishika and Shivika as at 31st March, 2024Liabilities Amount (₹) Assets Amount (₹) Capitals: Equipment 45,00,000 Rishika – ₹30,00,000
Shivika – ₹20,00,00050,00,000 Investments 5,00,000 Shivika’s Husband’s Loan 5,00,000 Debtors 35,00,000 Creditors 40,00,000 Stock 8,00,000 Cash at Bank 2,00,000 Total 95,00,000 Total 95,00,000 The firm was dissolved on the above date and the following transactions took place:
(i) Equipements were given to creditors in full settlement of their account.
(ii) Investments were sold at a profit of 20% on its book value.
(iii) Full amount was collected from debtors.
(iv) Stock was taken over by Rishika at 50% discount.
(v) Actual expenses of realisation amounted to ₹ 2,00,000 which were paid by the firm. Prepare Realisation Account.- CBSE CLASS XII - 2025
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Concepts Used:
Aldehydes, Ketones, and Carboxylic Acids
Aldehydes, Ketones, and Carboxylic Acids are carbonyl compounds that contain a carbon-oxygen double bond. These organic compounds are very important in the field of organic chemistry and also have many industrial applications.
Aldehydes:
Aldehydes are organic compounds that have the functional group -CHO.
Preparation of Aldehydes
Acid chlorides are reduced to aldehydes with hydrogen in the presence of palladium catalyst spread on barium sulfate.
Ketones:
Ketones are organic compounds that have the functional group C=O and the structure R-(C=O)-R’.
Preparation of Ketones
Acid chlorides on reaction with dialkyl cadmium produce ketones. Dialkyl cadmium themselves are prepared from Grignard reagents.
Carboxylic Acid:
Carboxylic acids are organic compounds that contain a (C=O)OH group attached to an R group (where R refers to the remaining part of the molecule).
Preparation of Carboxylic Acids
Primary alcohols are readily oxidized to carboxylic acids with common oxidizing agents such as potassium permanganate in neutral acidic or alkaline media or by potassium dichromate and chromium trioxide in acidic media.