Question:

How many of the integers 1, 2, … , 120, are divisible by none of 2, 5 and 7?

Updated On: Sep 15, 2024
  • 40
  • 42
  • 43
  • 41
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The Correct Option is D

Approach Solution - 1

The required answer = \(120×\bigg(1-\frac{1}{2}\bigg)×\bigg(1-\frac{1}{5}\bigg)×\bigg(1-\frac{1}{7}\bigg) = 41.14\)

Required answer is the integral part of \(41.14 =41\)

So, the correct option is (D): \(41\)

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Approach Solution -2

The number of multiples of 2 between 1 and 120 = 60
The number of multiples of 5 between 1 and 120 which are not multiples of 2 = 12
The number of multiples of 7 between 1 and 120 which are not multiples of 2 and 5 = 7
So, number of the integers 1, 2,..., 120, which are divisible by none of 2, 5 and 7 = 120-60-12-7= 41
∴ Required Numbers are 41.

So, the correct option is (D): \(41\)

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