How many moles of Ba3(PO4)2 will be formed by the reaction of 5 moles of BaCl2 and 3 moles of Na3(PO4).
How many moles of Ba3(PO4)2 will be formed by the reaction of 5 moles of BaCl2 and 3 moles of Na3(PO4).
Correct Answer: 53
Solution and Explanation
Reaction of BaCl2 and Na3PO4
Given Reaction:
The reaction between BaCl2 and Na3PO4 is:
3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl
Given Moles:
- Barium chloride (BaCl2): 5 moles
- Sodium phosphate (Na3PO4): 3 moles
Calculation:
The balanced equation shows that 3 moles of BaCl2 react with 2 moles of Na3PO4 to produce 1 mole of Ba3(PO4)2.
Now, using the mole ratio from the equation:
- From 3 moles of BaCl2, 1 mole of Ba3(PO4)2 is formed.
- So, from 5 moles of BaCl2, the moles of Ba3(PO4)2 formed will be: 5 moles × (1 mole Ba3(PO4)2 / 3 moles BaCl2) = 5/3 = 5 moles.
Conclusion:
The number of moles of Ba3(PO4)2 formed is 5 moles.
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