Question

How many isomers of monobromoderivatives are obtained on bromination of the following compound ?

• A. $4$
• B. $3$
• C. $2$
• D. $5$

Hint:

Number of monohalogen derivatives equals the number of nonequivalent hydrogen atoms in the molecule.

Answer 1

The Correct Option is A

Step 1: Identify the given hydrocarbon.
The given structure represents isopentane (2-methylbutane). It contains different types of hydrogen atoms due to its branched structure.

Step 2: Identify distinct hydrogen positions.
In isopentane, there are four nonequivalent types of hydrogen atoms:
Primary hydrogens at two different positions, secondary hydrogen, and tertiary hydrogen.

Step 3: Effect of bromination.
During monobromination, bromine can substitute hydrogen atoms at each nonequivalent position, leading to different structural isomers.

Step 4: Count of monobrominated products.
Since there are four different types of hydrogen atoms, four different monobromoderivatives are formed.

Step 5: Conclusion.
Therefore, the number of isomers of monobromoderivatives obtained is $4$.