Question:

How many five-digit numbers can be formed using the digits 2, 3, 8, 7, 5 exactly once such that the number is divisible by 125?

Show Hint

When checking divisibility rules, focus on the last digits of the number first, especially for divisibility by 125 or 5.
Updated On: Aug 4, 2025
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The Correct Option is A

Solution and Explanation

A number is divisible by 125 if its last three digits are divisible by 125. We need to find the last three digits of the number formed from 2, 3, 8, 7, and 5 such that it is divisible by 125. The last three digits must be 125, but the digits 1 and 5 are not in the set of available digits (2, 3, 8, 7, 5). Therefore, no number can be formed that is divisible by 125.
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