Question

How many electrons are involved in the reaction when 0.40 F of electricity is passed through an electrolytic solution?

• A. \( 6.642 \times 10^{25} \)
• B. \( 2.4088 \times 10^{23} \)
• C. \( 1.505 \times 10^{24} \)
• D. \( 6.022 \times 10^{23} \)

Hint:

To calculate the number of electrons involved in a reaction, use Faraday’s constant and the amount of charge passed through the solution.

Answer 1

The Correct Option is B

Step 1: Using the relation between charge and moles of electrons.
The amount of electricity in Faradays (F) is related to the number of moles of electrons by the equation: \[ n = \frac{Q}{F} \] Where: - \(Q = 0.40 \, \text{F}\) (charge passed), - \(F = 96,485 \, \text{C/mol}\) (Faraday constant).
Step 2: Calculation.
We can calculate the number of electrons as: \[ n = \frac{0.40}{96,485} \times 6.022 \times 10^{23} = 2.4088 \times 10^{23} \, \text{electrons} \]
Step 3: Conclusion.
The correct answer is (B) \( 2.4088 \times 10^{23} \).