When dividing an inequality by a negative number, remember that the direction of the inequality reverses. This is an important rule to consider when solving inequalities involving negative divisors.
The correct answer is: (B): \( \frac{a}{x} > \frac{b}{x} \)
We are given that \( a \), \( b \), and \( x \) are real numbers such that \( a < b \) and \( x < 0 \). We are tasked with determining the relationship between \( \frac{a}{x} \) and \( \frac{b}{x} \).
Step 1: Understanding the implications of \( a < b \) and \( x < 0 \)
We are given that \( a < b \), so initially, it would seem that \( \frac{a}{x} \) should be less than \( \frac{b}{x} \). However, since \( x < 0 \), we must consider how dividing by a negative number affects the inequality.
Step 2: Dividing by a negative number
When you divide both sides of an inequality by a negative number, the direction of the inequality reverses. So, dividing \( a < b \) by the negative number \( x \) gives:
Step 3: Conclusion
Thus, since \( x < 0 \), the inequality reverses, and we have \( \frac{a}{x} > \frac{b}{x} \), which means the correct answer is (B): \( \frac{a}{x} > \frac{b}{x} \).
Find the approximate value of (25.2)1/2.
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: