Question

Given: \( E = E_0 \sin(kx - \omega t),\ B = B_0 \sin(kx - \omega t) \). Choose correct relation.

• A. \( E_0 k = B_0 \omega \)
• B. \( E_0 = B_0 k \)
• C. \( E_0 = B_0 \omega \)
• D. \( E_0 = \frac{\omega}{k} \)

Hint:

Electromagnetic waves satisfy \( E_0 k = B_0 \omega \), derived from Maxwell’s laws.

Answer 1

The Correct Option is A

From Maxwell’s equations, in electromagnetic wave: \[ \frac{E_0}{B_0} = c = \frac{\omega}{k} \Rightarrow E_0 k = B_0 \omega \]