To evaluate the given statements regarding SN2 and SN1 reactions, let's delve into the concepts:
Explanation: SN2 reactions involve a one-step, bimolecular nucleophilic substitution mechanism. The nucleophile attacks the carbon atom from the side opposite to the leaving group, leading to an inversion of configuration at the chiral center, known as the Walden inversion. Thus, the product is stereospecific as it results in a specific stereoisomer.
Explanation: SN1 reactions occur via a two-step mechanism where the first step involves the formation of a carbocation intermediate. Since the carbocation is planar, the nucleophile can attack from either face of the carbocation, leading to the formation of both enantiomers in equal proportion. As a result, the product is a racemic mixture.
Thus, both statements I and II are accurate as per the standard chemical reaction mechanisms for SN2 and SN1 reactions. Therefore, the correct answer is:
Both Statement I and Statement II is true
S$_\text{N}2$ reactions are stereospecific and proceed via a backside attack, resulting in the inversion of configuration at the chiral center.
S$_\text{N}1$ reactions occur via a carbocation intermediate, which is planar. As a result, nucleophiles can attack from either side, leading to a racemic mixture of products.
Thus:
\[ \text{S$_\text{N}2$} \rightarrow \text{Inversion (stereospecific)}, \quad \text{S$_\text{N}1$} \rightarrow \text{Racemization}. \]
Both statements are correct.
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: