S$_\text{N}2$ reactions are stereospecific and proceed via a backside attack, resulting in the inversion of configuration at the chiral center.
S$_\text{N}1$ reactions occur via a carbocation intermediate, which is planar. As a result, nucleophiles can attack from either side, leading to a racemic mixture of products.
Thus:
\[ \text{S$_\text{N}2$} \rightarrow \text{Inversion (stereospecific)}, \quad \text{S$_\text{N}1$} \rightarrow \text{Racemization}. \]
Both statements are correct.
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)