Statement I: Ultraviolet (UV) rays have the highest frequency among the given options (microwaves, infrared rays, and ultraviolet rays). Since the energy of a photon is directly proportional to its frequency (\( E = h f \)), UV rays are the most effective for the emission of electrons from a metallic surface. Hence, Statement I is true.
Statement II: The maximum kinetic energy of photoelectrons is given by the photoelectric equation: \[ K.E_{\text{max}} = h f - h f_0, \] where \( h \) is Planck's constant, \( f \) is the frequency of the incident light, and \( f_0 \) is the threshold frequency. From the equation, it is clear that \( K.E_{\text{max}} \) is directly proportional to \( f \), not inversely proportional.
Hence, Statement II is false. Thus, the correct answer is \( \boxed{(3)} \).

Which of the following statements are correct, if the threshold frequency of caesium is $ 5.16 \times 10^{14} \, \text{Hz} $?
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:

Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
If $ \theta \in [-2\pi,\ 2\pi] $, then the number of solutions of $$ 2\sqrt{2} \cos^2\theta + (2 - \sqrt{6}) \cos\theta - \sqrt{3} = 0 $$ is: