Given below are two statements : Statement I : On heating with \(KHSO _4\), glycerol is dehydrated and acrolein is formed
Statement II : Acrolein has fruity odour and can be used to test glycerol's presence Choose the correct option
Statement II : Acrolein has fruity odour and can be used to test glycerol's presence Choose the correct option
- Both Statement I and Statement II are correct.
- Both Statement I and Statement II are incorrect
- Statement I is correct but Statement II is incorrect.
- Statement I is incorrect but Statement II is correct.
The Correct Option is C
Solution and Explanation
Therefore, the correct option is (C): Statement I is correct but Statement II is incorrect.
Top Questions on Aldehydes, Ketones and Carboxylic Acids
- An organic compound (X) having molecular formula C$_5$H$_10$O can show various properties depending on its structures. Draw each of the structures if it:
(I) shows Cannizzaro reaction.
(II) reduces Tollens' reagent and has a chiral carbon.
(III) gives positive iodoform test.- CBSE CLASS XII - 2025
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In the given reaction sequence, the structure of Y would be:
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(i) Aldol (ii) Schiff's base (iii) Cannizaro's reaction (iv) Oxime (v) Acetal- UP Board XII - 2025
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CH$_3$CH=CHCH$_3$ $\xrightarrow{X}$ CH$_3$COOH $\xrightarrow{Y}$ CH$_3$CO-Cl $\xrightarrow{Z, C6H5NH2}$ C$_6$H$_5$NHCOCH$_3$- TS EAMCET - 2025
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Questions Asked in JEE Main exam
In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:
- JEE Main - 2025
- Electromagnetic Field (EMF)
Given below are two statements:
Statement I:
will undergo alkaline hydrolysis at a faster rate than 
Statement II:
In
intramolecular substitution takes place first by involving lone pair of electrons on nitrogen.
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The effect of temperature on the spontaneity of reactions are represented as: Which of the following is correct?
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- Thermodynamics and Work Done
- Let \( \vec{a} = \hat{i} + 2\hat{j} + \hat{k} \) and \( \vec{b} = 2\hat{i} + 7\hat{j} + 3\hat{k} \). Let \( L_1 : \vec{r} = (-\hat{i} + 2\hat{j} + \hat{k}) + \lambda \vec{a}, \lambda \in {R} \) and \( L_2 : \vec{r} = (\hat{j} + \hat{k}) + \mu \vec{b}, \mu \in \mathbb{R} \) be two lines. If the line \( L_3 \) passes through the point of intersection of \( L_1 \) and \( L_2 \), and is parallel to \( \vec{a} + \vec{b} \), then \( L_3 \) passes through the point:
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If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
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- permutations and combinations
Concepts Used:
Aldehydes, Ketones, and Carboxylic Acids - Physical Properties
The following are the Physical Properties of Aldehydes, Ketones, and Carboxylic Acids:
The physical properties of aldehydes and ketones are stated below:
Physical State:
While Ethanal is a volatile liquid, Methanal is a gas at room temperature. Similarly, other aldehydes and ketones are either gas or liquid at room temperature.
Boiling point: The boiling point of methanal is -19o C and for ethanal it is +21o C. From this we can say that the boiling point of ethanal is close to room temperature. Generally the boiling point of aldehydes and ketones increases with increase in molecular weight. Boiling point depends upon the strength of the intermolecular forces.
- Vander Waals Dispersion Force: The boiling point of aldehydes and ketones depend on the carbon atoms. When the molecules lengthen and the number of electrons increases, the bond increases and the boiling point increases.
- Van Der Waals dipole-dipole attraction: Due to the presence of the double bond between carbon and oxygen, aldehydes and ketones are polar to each other. This leads to an attraction between the permanent dipoles and other molecules near it. This is what makes the boiling point of these compounds high.
Solubility:
Aldehydes and ketones are soluble in water. The solubility decreases when the length of the alkyl chain increases. Aldehydes and ketones like methanol, ethanal and propanone are miscible in water of all quantities. These compounds cannot form hydrogen bonds on their own but are able to do so with water due to the dipole-dipole attraction.
Smell:
All lower aldehydes have a strong and unpleasant smell. Other aldehydes and ketones have a pleasant smell. When the molecule size of the compounds increases, the smell becomes less pungent. Naturally occurring aldehydes and ketones are used regularly in flavouring agents and perfumes like vanilla flavoring.
The physical properties of carboxylic acids are stated below:
Physical state:
Carboxylic acids, at room temperature, are colourless liquids. These acids have nine carbon atoms or less. Higher acids are more waxy and are solid.
Boiling Point:
Compared to aldehydes, ketones and other compounds of similar molecular masses, carboxylic acids have high boiling points. The reason behind such high boiling points is for the acid molecules ability to substantially associate with each other through intermolecular hydrogen bonding. The hydrogen bonds do not break up completely even in the vapour state as a result. Most carboxylic acids are present as dimers in the vapour state.
Smell:
At room temperature, carboxylic acids have shown to possess unpleasant odours.
Solubility:
The more simple aliphatic components of carboxylic acids have four carbon atoms and are miscible or soluble in water. This is due to its ability to form hydrogen bonds with water. When the number of atoms in the carboxylic acids is increased, the solubility nature decreases. For higher members of the same group, the immiscibility nature can be attributed to its hydrophobic communication of the hydrocarbon part of the acid. However, they are able to become soluble in organic solvents that are less polar like alcohol, benzene, ether etc.