Given below are two statements:
Statement I: [Ni(CN)4]2– is square planar and diamagnetic complex, with dsp2 hybridization for Ni but [Ni(CO)4] is tetrahedral, paramagnetic and with sp3-hybridization for Ni.
Statement II: [NiCl4]2– and [Ni(CO)4] both have same d-electron configuration, have same geometry and are paramagnetic.
In light of the above statements, choose the correct answer from the options given below :
Given below are two statements:
Statement I: [Ni(CN)4]2– is square planar and diamagnetic complex, with dsp2 hybridization for Ni but [Ni(CO)4] is tetrahedral, paramagnetic and with sp3-hybridization for Ni.
Statement II: [NiCl4]2– and [Ni(CO)4] both have same d-electron configuration, have same geometry and are paramagnetic.
In light of the above statements, choose the correct answer from the options given below :
- Both Statement I and Statement II are true
- Both Statement I and Statement II are false
- Statement I is correct but Statement II is false
- Statement I is incorrect but Statement II is true
The Correct Option is B
Solution and Explanation
The correct answer is (B) : Both Statement I and Statement II are false.
\([Ni(CN)_4]^{2– }\)is square planar and diamagnetic with μ = 0 , its hybridisation is dsp2
\(Ni(CO)_4\) is tetrahedral but diamagnetic.
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Concepts Used:
Hybridisation
Hybridization refers to the concept of combining atomic orbitals in order to form new hybrid orbitals that are appropriate to represent their bonding properties. Hybridization influences the bond length and bond strength in organic compounds.
Types of Hybridization:
sp Hybridization
sp hybridization is observed while one s and one p orbital inside the identical principal shell of an atom mix to shape two new equal orbitals. The new orbitals formed are referred to as sp hybridized orbitals.
sp2 Hybridization
sp2 hybridization is observed whilst ones and p orbitals of the same shell of an atom blend to shape three equivalent orbitals. The new orbitals formed are referred to as sp2 hybrid orbitals.
sp3 Hybridization
When one ‘s’ orbital and 3 ‘p’ orbitals belonging to the identical shell of an atom blend together to shape 4 new equal orbitals, the sort of hybridization is referred to as a tetrahedral hybridization or sp3.
sp3d Hybridization
sp3d hybridization involves the joining of 3p orbitals and 1d orbital to form 5 sp3d hybridized orbitals of identical energy. They possess trigonal bipyramidal geometry.
sp3d2 Hybridization
With 1 s three p’s and two d’s, there is a formation of 6 new and identical sp3d2 orbitals.