Question:

Given below are two statements:
Statement I: In an LCR series circuit, current is maximum at resonance. 
Statement II: Current in a purely resistive circuit can never be less than that in a series LCR circuit when connected to the same voltage source. 
In the light of the above statements, choose the correct from the options given below.

Updated On: Mar 22, 2025
  • Statement I is true but Statement II is false
  • Statement I is false but Statement II is true
  • Both Statement I and Statement II are true
  • Both Statement I and Statement II are false
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Statement-I: \[ I_m = \frac{V_m}{\sqrt{R^2 + (X_L - X_C)^2}} \] At resonance, \(X_L = X_C\), so: \[ I_m = \frac{V_m}{R} \]

Thus, the impedance is minimum, and therefore, \(I\) is maximum at resonance.

Statement-II: \[ I = \frac{V}{R} \] In a purely resistive circuit.

Hence, in a purely resistive circuit, the current cannot be less than that in a series LCR circuit.

Thus, both Statement I and Statement II are true.

Was this answer helpful?
0
0