Question:
Given below are two statements.
Statement I: First ionisation enthalpy of Cr is greater than that of Mn.
Statement II: Second and third ionisation enthalpies of Cr are less than that of Mn.
In the light of above statements, choose the correct option.
Given below are two statements.
Statement I: First ionisation enthalpy of Cr is greater than that of Mn.
Statement II: Second and third ionisation enthalpies of Cr are less than that of Mn.
In the light of above statements, choose the correct option.
Show Hint
Ionisation enthalpies depend on the stability of the electron configuration, and Cr has a more stable configuration than Mn after the first ionisation.
Updated On: Jan 29, 2026
- Both statement I and statement II are correct
- Both statement I and statement II are incorrect
- Statement I is correct but statement II is incorrect
- Statement I is incorrect but statement II is correct
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Analyze statement I.
The first ionisation enthalpy of Cr is indeed greater than that of Mn. This is due to the fact that Cr has a more stable electron configuration (3d\(^5\)4s\(^1\)) compared to Mn, which makes it harder to remove an electron. Step 2: Analyze statement II.
However, the second and third ionisation enthalpies of Cr are higher than those of Mn. This is because, after the removal of the first electron, Cr becomes a stable ion with a half-filled d-subshell, making it harder to remove additional electrons compared to Mn. Step 3: Conclusion.
Thus, Statement I is correct, but Statement II is incorrect. Final Answer: \[ \boxed{\text{Statement I is correct but statement II is incorrect}}. \]
The first ionisation enthalpy of Cr is indeed greater than that of Mn. This is due to the fact that Cr has a more stable electron configuration (3d\(^5\)4s\(^1\)) compared to Mn, which makes it harder to remove an electron. Step 2: Analyze statement II.
However, the second and third ionisation enthalpies of Cr are higher than those of Mn. This is because, after the removal of the first electron, Cr becomes a stable ion with a half-filled d-subshell, making it harder to remove additional electrons compared to Mn. Step 3: Conclusion.
Thus, Statement I is correct, but Statement II is incorrect. Final Answer: \[ \boxed{\text{Statement I is correct but statement II is incorrect}}. \]
Was this answer helpful?
0
0
Top Questions on Acidic and Basic Oxides
- 5.8 g of Aniline is converted into benzanilide with some reaction sequences. Calculate the mass of benzanilide formed, if percentage yield of reaction is 82%. \[ \text{Ph} - \text{COCl} + \text{PhNH}_2 \xrightarrow{\text{Py}} \text{Benzanilide} \]
- JEE Main - 2026
- Chemistry
- Acidic and Basic Oxides
- If \( x |x - 3| + 3 |x - 2| + 1 = 0 \), then the number of real solutions is.
- JEE Main - 2025
- Chemistry
- Acidic and Basic Oxides
Consider the following oxides:
V_2O_5, Cr_2O_3, Mn_2O_7, V_2O_3, VO_2
A number of oxides which are acidic is \( x \).
Consider the following complex compound:
[Co(NH_2CH_2CH_2NH_2)_3](SO_4)_3
The primary valency of the complex is \( y \).
What is the value of \( x + y \) is?- JEE Main - 2025
- Chemistry
- Acidic and Basic Oxides
Given below are two statements:
Statement (I): \(\textit{An element in the extreme left of the periodic table forms acidic oxides.}\)
Statement (II):\( \textit{Acid is formed during the reaction between water and oxide of a reactive element present in the extreme right of the periodic table.} In the light of the above statements, choose the correct answer from the options given below:\)- JEE Main - 2025
- Chemistry
- Acidic and Basic Oxides
- What is the equivalent weight of sulphuric acid (H2SO4) in a reaction where it donates 2 H+ ions?
- AP EAPCET - 2025
- Chemistry
- Acidic and Basic Oxides
View More Questions
Questions Asked in JEE Main exam
- Electromagnetic wave with intensity \( I = 4 \times 10^{14} \, \text{watt/m}^2 \) is propagating in free space. Find the amplitude of magnetic field \( B_0 \). Given: \( c = 3 \times 10^8 \, \text{m/s}, \epsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \).
- JEE Main - 2026
- Spectroscopy
- For the given statements below, mark the correct option. Statement-I: Work done by a conservative force \( f \), from \( r_1 \) to \( r_2 \) is given by: \[ W = \int_{r_1}^{r_2} f \, dr. \] Statement-II: Work done by conservative force is path dependent.
- JEE Main - 2026
- Semiconductor electronics: materials, devices and simple circuits
- Statement-1: Time period of simple pendulum is increased if density of material of pendulum is increased. Statement-2: Time period of simple pendulum is \( T = 2 \pi \sqrt{\frac{l}{g}} \).
- JEE Main - 2026
- Semiconductor electronics: materials, devices and simple circuits
- A capacitor of capacitance 10 μF is connected with a battery of emf 6V. Now the battery is disconnected and another uncharged capacitor of capacitance 20 μF is connected to the capacitor. Find the charge on the 20 μF capacitor.
- JEE Main - 2026
- Rotational Motion and Torque
- Find the percentage change in height risen by liquid if density of fluid, radius of capillary, and surface tension of liquid are decreased by 1%. Assume contact angle doesn’t change and capillary is of sufficient length.
- JEE Main - 2026
- Electrostatics and Work Done by Electric Field
View More Questions