Question

What is the equivalent weight of sulphuric acid (H₂SO₄) in a reaction where it donates 2 H⁺ ions?

• A. 49
• B. 98
• C. 24.5
• D. 36.5

Hint:

Always divide molar mass by the number of H\textsuperscript{+} ions an acid donates to find its equivalent weight.

Answer 1

The Correct Option is A

To find the equivalent weight of sulfuric acid (H₂SO₄) in a reaction where it donates 2 H⁺ ions, we use the formula for equivalent weight:

Equivalent Weight = \(\frac{\text{Molar Mass}}{\text{n-factor}}\)

The molar mass of H₂SO₄ is calculated as:

• Hydrogen: 2 atoms × 1.01 g/mol = 2.02 g/mol
• Sulfur: 1 atom × 32.07 g/mol = 32.07 g/mol
• Oxygen: 4 atoms × 16.00 g/mol = 64.00 g/mol

Adding these gives the total molar mass of sulfuric acid:

2.02 + 32.07 + 64.00 = 98.09 g/mol

For simplicity, we use the approximate molar mass as 98 g/mol.

In this reaction, sulfuric acid donates 2 H⁺ ions, so the n-factor is 2.

Plug these values into the formula:

Equivalent Weight = \(\frac{98 \text{ g/mol}}{2}\) = 49 g/equiv

Thus, the equivalent weight of sulfuric acid in this reaction is 49 g/equiv.