To solve the problem, let's evaluate the two given statements:
Statement I: "Diamagnetic Li₂ molecules are known to exist in the vapor phase."
This statement is correct. Lithium (Li) has two electrons, and when two lithium atoms form a molecule (Li₂), the two electrons pair up in the bonding molecular orbital, resulting in no unpaired electrons. As a result, Li₂ is diamagnetic and can exist in the vapor phase under appropriate conditions.
Statement II: "According to M.O theory, the double bond in C₂ consists of both π bonds."
This statement is incorrect. In the molecule \( C_2 \), the bonding involves both sigma and pi bonds. According to Molecular Orbital (M.O.) theory, the double bond in \( C_2 \) consists of one sigma bond and one pi bond, not two pi bonds. Therefore, Statement II is incorrect.
Conclusion: Since Statement I is correct, but Statement II is not.
Final Answer:
The correct option is (C) Statement I is correct, but Statement II is not correct.
Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is (are):
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
The percentage error in the measurement of mass and velocity are 3% and 4% respectively. The percentage error in the measurement of kinetic energy is: