Statement I is correct because aniline does react with concentrated sulfuric acid and, upon heating, forms p-aminobenzene sulfonic acid, which gives a blood red color in Tassaigne’s test.
Statement II is also correct as in Friedel-Crafts alkylation and acylation reactions, aniline forms a salt with the \(\text{AlCl}_3\) catalyst. This interaction results in a positive charge on nitrogen, causing it to act as a deactivating group, making further substitution reactions difficult on the benzene ring.
Thus, both statements are true.
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