Given below are two statements :
Statement I: An elevator can go up or down with uniform speed when its weight is balanced with the tension of its cable
Statement II: Force exerted by the floor of an elevator on the foot of a person standing on it is more than his/her weight when the elevator goes down with increasing speed
In the light of the above statements, choose the correct answer from the options given below:
Statement-1:
When the elevator is moving with uniform speed, the tension in the rope is equal to the gravitational force:
\[ T = F_g \]
Where \( T \) is the tension in the rope, and \( F_g \) is the gravitational force acting downward.
Statement-2:
When the elevator is going down with increasing speed, its acceleration is downward. The force balance equation can be written as:
\[ W - N = \frac{W}{g} \times a \]
Simplifying the equation:
\[ N = W \left(1 - \frac{a}{g}\right) \]
Hence, the normal force \( N \) is less than the weight \( W \), since the elevator's downward acceleration reduces the normal force felt by the object inside the elevator.
Therefore, Statement I is true but Statement II is false
Two blocks of masses \( m \) and \( M \), \( (M > m) \), are placed on a frictionless table as shown in figure. A massless spring with spring constant \( k \) is attached with the lower block. If the system is slightly displaced and released then \( \mu = \) coefficient of friction between the two blocks.
(A) The time period of small oscillation of the two blocks is \( T = 2\pi \sqrt{\dfrac{(m + M)}{k}} \)
(B) The acceleration of the blocks is \( a = \dfrac{kx}{M + m} \)
(\( x = \) displacement of the blocks from the mean position)
(C) The magnitude of the frictional force on the upper block is \( \dfrac{m\mu |x|}{M + m} \)
(D) The maximum amplitude of the upper block, if it does not slip, is \( \dfrac{\mu (M + m) g}{k} \)
(E) Maximum frictional force can be \( \mu (M + m) g \)
Choose the correct answer from the options given below:
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is 
For a statistical data \( x_1, x_2, \dots, x_{10} \) of 10 values, a student obtained the mean as 5.5 and \[ \sum_{i=1}^{10} x_i^2 = 371. \] He later found that he had noted two values in the data incorrectly as 4 and 5, instead of the correct values 6 and 8, respectively.
The variance of the corrected data is:
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.
Mathematically, we express the second law of motion as follows:

Newton’s 3rd law states that there is an equal and opposite reaction for every action.