The dipole moment is a vector quantity. In the trans isomer of 2-butene, the dipoles of substituents are equal in magnitude but opposite in direction, resulting in a net dipole moment of zero (\(\mu = 0\)). However, in the cis isomer, the dipoles do not cancel out, making the molecule polar with \(\mu > 0\). Thus, the dipole moment of the cis form is greater than the trans form.
Cis isomer: \(\mu > 0\), Trans isomer: \(\mu = 0\).
Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.
List - I (Pair of Compounds) | List - II (Isomerism) |
---|---|
(A) n-propanol and Isopropanol | (I) Metamerism |
(B) Methoxypropane and ethoxyethane | (IV) Functional Isomerism |
(C) Propanone and propanal | (III) Position Isomerism |
(D) Neopentane and Isopentane | (II) Chain Isomerism |