
The dipole moment is a vector quantity. In the trans isomer of 2-butene, the dipoles of substituents are equal in magnitude but opposite in direction, resulting in a net dipole moment of zero (\(\mu = 0\)). However, in the cis isomer, the dipoles do not cancel out, making the molecule polar with \(\mu > 0\). Thus, the dipole moment of the cis form is greater than the trans form.
Cis isomer: \(\mu > 0\), Trans isomer: \(\mu = 0\).
Therefore, both the assertion and reason are true, and the reason correctly explains the assertion.
Draw the possible isomers of:
\[ [ \text{Co}(\text{en})_2\text{Cl}_2 ]^+ \]


In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by: