The correct answer is (B): Both (A) and (R) are true but (R) is not the correct explanation of (A).
The outer most shell of Boron is 2 and its maximum covalency is 4.
Therefore, boron cannot form BF63-.
Hence Assertion is correct.
Boron is the first element of group-13 of modern periodic table. It is very small in size.
But it does not provide correct explanation of Assertion.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Consider the following reaction:
\[ A + NaCl + H_2SO_4 \xrightarrow[\text{Little amount}]{} CrO_2Cl_2 + \text{Side products} \] \[ CrO_2Cl_2(\text{Vapour}) + NaOH \rightarrow B + NaCl + H_2O \] \[ B + H^+ \rightarrow C + H_2O \]
The number of terminal 'O' present in the compound 'C' is ________.
At steady state, the charge on the capacitor, as shown in the circuit below, is -----\( \mu C \). 