Question

Given below are some nitrogen containing compounds:
Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume ...... mg of HCl.
(Given Molar mass in g mol\(^{-1}\): C = 12, H = 1, O = 16, Cl = 35.5.)

Answer 1

Correct Answer: 341

To solve this problem, we need to identify the most basic compound among the given options and then calculate the amount of HCl consumed by 1.0 g of that compound.

1. Identifying the Most Basic Compound:
We need to compare the basicity of 4-nitroaniline, benzylamine, N-phenylacetamide, and aniline. Basicity depends on the availability of the nitrogen lone pair for protonation.

2. Basicity Analysis:
4-Nitroaniline: Nitro group is electron-withdrawing, reducing basicity.
Benzylamine: Nitrogen attached to a benzyl group, more basic than aniline.
N-Phenylacetamide: Amide, very weakly basic due to resonance with the carbonyl group.
Aniline: Lone pair delocalized into the benzene ring, reducing basicity.
Therefore, benzylamine is the most basic compound.

3. Calculating Molar Mass of Benzylamine ($C_7H_9N$):
Molar mass = (7 × 12) + (9 × 1) + (1 × 14) = 84 + 9 + 14 = 107 g/mol

4. Calculating Moles of Benzylamine:
Given 1.0 g of benzylamine, moles = mass / molar mass = 1.0 g / 107 g/mol = 1/107 mol

5. Reaction with HCl:
Benzylamine reacts with HCl in a 1:1 molar ratio: $C_7H_9N + HCl \rightarrow C_7H_9NH^+Cl^-$
So, 1/107 moles of benzylamine reacts with 1/107 moles of HCl.

6. Calculating Molar Mass of HCl:
Molar mass = 1 (for H) + 35.5 (for Cl) = 36.5 g/mol

7. Calculating Mass of HCl Consumed:
Mass of HCl = moles × molar mass = (1/107 mol) × (36.5 g/mol) = 36.5 / 107 g

8. Converting to Milligrams:
Mass of HCl (in mg) = (36.5 / 107) × 1000 mg ≈ 0.3411 × 1000 mg ≈ 341.1 mg

Final Answer:
1.0 g of benzylamine will consume approximately 341.1 mg of HCl.