\((-∞, -\frac {1}{\sqrt 5}]∪(\frac {1}{\sqrt 5},0)\)
\((-\frac {1}{\sqrt 5},0)∪(0,\frac {1}{\sqrt 5} )\)
\((0,\frac {1}{\sqrt 5})∪(\frac {1}{\sqrt 5} ,∞)\)
\((-\sqrt {\frac 25},0)∪(\sqrt {\frac 25},∞)\)
The correct option is (D): \((-\sqrt {\frac 25},0)∪(\sqrt {\frac 25},∞)\)
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to:
Increasing Function:
On an interval I, a function f(x) is said to be increasing, if for any two numbers x and y in I such that x < y,
⇒ f(x) ≤ f(y)
Decreasing Function:
On an interval I, a function f(x) is said to be decreasing, if for any two numbers x and y in I such that x < y,
⇒ f(x) ≥ f(y)
Strictly Increasing Function:
On an interval I, a function f(x) is said to be strictly increasing, if for any two numbers x and y in I such that x < y,
⇒ f(x) < f(y)
Strictly Decreasing Function:
On an interval I, a function f(x) is said to be strictly decreasing, if for any two numbers x and y in I such that x < y,
⇒ f(x) > f(y)