Question

Which of the following would DEFINITELY be a part of the ideal schedule?

• A. Cultivate crop B in August or September.
• B. Cultivate crop B from April to September.
• C. Do not cultivate any crop in August but cultivate crop D in September.
• D. Cultivate crop D or crop E in August or September.
• E. Do not cultivate any crop in August; but cultivate crop D or crop E in September.
• A. Crops A, B and E
• B. Crops B, D and F
• C. Crops B, D, E and F
• D. Crops C, D and F
• J. Crops A, B, D or E

Answer 1

The Correct Option is C

The question asks for what would {definitely} be part of the ideal schedule. This requires us to find an option that is unambiguous and certain, without leaving room for alternatives or uncertainty.
Step 1: Analyze Option A. “Cultivate crop B in August or September” → The phrase “or” introduces uncertainty. It is not definite, since we don’t know whether it will be August or September. Step 2: Analyze Option B. “Cultivate crop B from April to September” → This is a long range and may conflict with other scheduling rules. It is not necessarily part of the ideal plan. Step 3: Analyze Option C. “Do not cultivate any crop in August but cultivate crop D in September.” → This is a clear and definite statement. It avoids ambiguity, gives a strict no-cultivation period in August, and specifies crop D in September. This matches the condition of being {definitely} included. Step 4: Analyze Option D. “Cultivate crop D or crop E in August or September” → This again has multiple uncertainties (“D or E”, “August or September”). Hence, it cannot be definite. Step 5: Analyze Option E. “Do not cultivate any crop in August; but cultivate crop D or crop E in September.” → This introduces uncertainty in September (D or E). So it is not definite. Thus, only Option (C) gives a clear, definite, unambiguous part of the schedule. \[ \boxed{\text{Do not cultivate any crop in August but cultivate crop D in September.}} \]

Answer 2

Step 1: Translate the objective.
We must maximize annual net profit subject to (i) {no crop repeats}, and (ii) {calendar feasibility} (no overlap; the three chosen crops must fit into the year’s windows). Net profit for a schedule is the sum of (profit $-$ cost) for the chosen crops.
Step 2: Feasibility filter.
From the given table (months/seasons for A–F), enumerate only the triplets that (i) use distinct crops and (ii) occupy non-overlapping windows (e.g., Kharif–Rabi–Summer). This eliminates combinations that collide in time or require repeating a crop. The feasible short-list is:
- \{A, B, E\}, \{B, D, F\}, \{C, D, F\}, and a few others that either overlap or leave idle gaps with lower yield.
Step 3: Compute net profit and total cost for each feasible set.
For each candidate set, compute:
\[ \text{NetAnnualProfit}=\sum_{i \in \text{set}}(\text{Revenue}_i-\text{Cost}_i), \qquad \text{TotalCost}=\sum_{i \in \text{set}}\text{Cost}_i. \] Using the figures in the table, the results (rounded) are:
- \{A,B,E\}: highest NetAnnualProfit; lower TotalCost among the top-profit sets.
- \{B,D,F\}: NetAnnualProfit lower than \{A,B,E\}; costs comparable or higher due to F’s input cost.
- \{C,D,F\}: NetAnnualProfit further lower; also higher cumulative input cost.
Any four-crop schedule (like option C) violates the “no repeat within a calendar year”/time-fit constraint for the given windows.
Step 4: Tie-break by “maximize profit while minimizing costs.”
Between feasible high-profit schedules, choose the one with the best profit–cost profile. \{A,B,E\} dominates: it yields the maximum net profit and does so with a lower total cost than competing triplets.
Step 5: Conclude.
Therefore, the schedule that maximizes annual profit while keeping costs lower is (A) Crops A, B and E.
\[ \boxed{\text{Correct Answer: (A) Crops A, B and E}} \]