Question:

From the top of a 50 m tall building, the angles of depression to two points on the ground are \( 45^\circ \) and \( 30^\circ \). Find the distance between the two points.

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\textbf{Key Fact:} Use tangent of the angle of depression to find horizontal distances from the height.
Updated On: May 28, 2025
  • \( 20(\sqrt{3} - 1) \, \text{m} \)
  • \( 25(\sqrt{3} - 1) \, \text{m} \)
  • \( 30(\sqrt{3} - 1) \, \text{m} \)
  • \( 50(\sqrt{3} - 1) \, \text{m} \)
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The Correct Option is D

Solution and Explanation

To solve this problem, we need to find the horizontal distance between two points on the ground from which the angles of depression \(45^\circ\) and \(30^\circ\) are observed from the top of a 50 m tall building.

We will use trigonometry to solve this. Let's denote:

  • \(A\) as the top of the building.
  • \(B\) as the point on the ground where the angle of depression is \(45^\circ\).
  • \(C\) as the point on the ground where the angle of depression is \(30^\circ\).
  • \(H = 50 \, \text{m}\) as the height of the building.
  • \(AB = x \) as the distance from the base of the building to point \(B\).
  • \(AC = y\) as the distance from the base of the building to point \(C\).

Step 1: Calculate \(x\) using \(45^\circ\) angle

For a \(45^\circ\) angle of depression, we use the tangent function:

\(\tan(45^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{H}{x}\)

Since \(\tan(45^\circ) = 1\), we have:

\(1 = \frac{50}{x} \Rightarrow x = 50 \text{ m}\)

Step 2: Calculate \(y\) using \(30^\circ\) angle

For a \(30^\circ\) angle of depression, we use the tangent function:

\(\tan(30^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{H}{y}\)

Since \(\tan(30^\circ) = \frac{1}{\sqrt{3}}\), we have:

\(\frac{1}{\sqrt{3}} = \frac{50}{y} \Rightarrow y = 50\sqrt{3} \text{ m}\)

Step 3: Find \(BC\), the distance between points \(B\) and \(C\)

The distance \(BC\) is the difference between \(AC\) and \(AB\):

\(BC = y - x = 50\sqrt{3} - 50\)

Factoring out 50 gives:

\(BC = 50(\sqrt{3} - 1) \text{ m}\)

Thus, the distance between the two points is \(\boldsymbol{50(\sqrt{3} - 1) \, \text{m}}\).

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