Step 1: Analyze the sets.
- Set 1: \( (x - 1)(x - 2) = 0 \) has solutions \( x = 1 \) or \( x = 2 \), which is a finite set.
- Set 2: The prime numbers less than 199 are finite, so this is also a finite set.
- Set 3: \( x^5 - 1 = 0 \) implies \( x = 1 \), which is a finite set.
- Set 4: The set of odd numbers is infinite because there is no limit to how many odd numbers exist.
Step 2: Conclusion.
Thus, the infinite set is option 4, which consists of all odd numbers in \( \mathbb{N} \). Therefore, the correct answer is 4. \( \{ x: x \in \mathbb{N} \text{ and } x \text{ is odd} \} \).
Let \( A = \{1,2,3\} \). The number of relations on \( A \), containing \( (1,2) \) and \( (2,3) \), which are reflexive and transitive but not symmetric, is ______.
Let \( S = \{p_1, p_2, \dots, p_{10}\} \) be the set of the first ten prime numbers. Let \( A = S \cup P \), where \( P \) is the set of all possible products of distinct elements of \( S \). Then the number of all ordered pairs \( (x, y) \), where \( x \in S \), \( y \in A \), and \( x \) divides \( y \), is _________.
Let \( A = (1, 2, 3, \dots, 20) \). Let \( R \subseteq A \times A \) such that \( R = \{(x, y) : y = 2x - 7 \} \). Then the number of elements in \( R \) is equal to: