Step 1: Understanding the Concept:
This question is based on a fundamental theorem in circle geometry. The theorem states that the lengths of the two tangents drawn from an external point to a circle are equal.
Step 2: Key Formula or Approach:
Theorem: If PA and PB are two tangents to a circle from an external point P, then PA = PB.
Step 3: Detailed Explanation:
According to the theorem, the lengths of the tangents from the external point P to the circle are equal.
We are given that PA and PB are the two tangents from point P.
The length of one tangent, PA, is given as 8 cm.
Therefore, the length of the other tangent, PB, must be equal to PA.
\[
PB = PA = 8 \text{ cm}
\]
Step 4: Final Answer:
The length of PB is 8 cm. This corresponds to option (B).
The length of a tangent of a circle of radius $3 \,\text{cm}$ drawn from a point at a distance of $5 \,\text{cm}$ from the centre will be:
$PQ$ is a chord of length $4\ \text{cm}$ of a circle of radius $2.5\ \text{cm}$. The tangents at $P$ and $Q$ intersect at a point $T$. Find the length of $TP$.