Fourier transform of \( x(t) = e^{-at}u(t - 2) \) is
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For signals involving exponential terms with unit step functions, remember to account for the shift in time and use standard Fourier transform results.
The Fourier transform of \( e^{-at}u(t-2) \), where \( u(t-2) \) is the unit step function shifted by 2, is given by:
\[
X(jw) = \int_{-\infty}^{\infty} e^{-at}e^{-j\omega t} dt
\]
Since the signal is shifted by 2, the Fourier transform will include a shift factor. The standard result for this type of transform is:
\[
X(jw) = \frac{e^{jw}}{a^2 + w^2}
\]
Therefore, the correct answer is option (1).