Question

Four quantum numbers of valence electron of sodium

• A. \(3, 0, 0, +\frac 12\)
• B. \(2, 1, 0, -\frac 12\)
• C. \(3, 0, -1, +\frac 12\)
• D. \(2, 0, 0, -\frac 12\)

Answer 1

The Correct Option is A

To solve the problem, we need to determine the four quantum numbers of the valence electron of sodium.

1. Understanding the Quantum Numbers:
Quantum numbers are used to describe the properties of an electron in an atom. The four quantum numbers are:

• Principal Quantum Number ($n$): Represents the energy level of the electron.
• Angular Momentum Quantum Number ($l$): Represents the subshell (orbital type) the electron occupies.
• Magnetic Quantum Number ($m_l$): Represents the orientation of the orbital in space.
• Spin Quantum Number ($m_s$): Represents the spin of the electron.

2. Valence Electron of Sodium:
Sodium (Na) has an atomic number of 11, so its electron configuration is:
$ 1s^2 \ 2s^2 \ 2p^6 \ 3s^1 $
The valence electron is in the 3rd shell (n = 3), in an s-orbital (l = 0), with a magnetic quantum number of 0 (since s-orbitals only have one orientation), and the spin quantum number can be either +1/2 or -1/2. Typically, the spin quantum number is taken as +1/2 for the first electron in the orbital.

3. Conclusion:
The four quantum numbers of the valence electron of sodium are:

• n = 3
• l = 0
• m_l = 0
• m_s = +1/2

 

Final Answer:
The correct set of quantum numbers is $ {(3, 0, 0, +1/2)} $.