Question

A photon has an energy of \( 3.2 \times 10^{-19} \, \text{J} \). What is the frequency of the photon?

• A. \( 5.0 \times 10^{14} \, \text{Hz} \)
• B. \( 4.0 \times 10^{14} \, \text{Hz} \)
• C. \( 3.0 \times 10^{14} \, \text{Hz} \)
• D. \( 6.0 \times 10^{14} \, \text{Hz} \)

Hint:

Remember: The energy of a photon is directly proportional to its frequency. The higher the frequency, the greater the energy of the photon.

Answer 1

The Correct Option is A

Step 1: Use the formula for energy of a photon The energy of a photon \( E \) is related to its frequency \( \nu \) by the equation: \[ E = h \nu \] where: - \( E \) is the energy of the photon, - \( h = 6.626 \times 10^{-34} \, \text{J} \cdot \text{s} \) is Planck's constant, - \( \nu \) is the frequency of the photon. Step 2: Solve for the frequency Rearranging the formula to solve for \( \nu \): \[ \nu = \frac{E}{h} \] Substitute the given values: \[ \nu = \frac{3.2 \times 10^{-19}}{6.626 \times 10^{-34}} = 4.83 \times 10^{14} \, \text{Hz} \] Answer: Therefore, the frequency of the photon is approximately \( 5.0 \times 10^{14} \, \text{Hz} \). So, the correct answer is option (1).