Step 1: Calculate the total number of seating arrangements without restrictions.
The total number of ways to arrange 4 persons in a row is \( 4! = 24 \).
Step 2: Subtract the number of arrangements where P and R sit adjacent to each other.
Treat P and R as a single "block," so we have 3 "objects" to arrange (the PR block, Q, and S). The number of ways to arrange these 3 objects is \( 3! = 6 \). Since P and R can be arranged within the block in 2 ways (P first or R first), the total number of arrangements where P and R sit adjacent is \( 6 \times 2 = 12 \).
Step 3: Apply the condition that S must be seated to the right of Q.
For the remaining valid arrangements, we need to consider only those where S is seated to the right of Q. Out of the total 12 arrangements, half will satisfy this condition, so there are \( \frac{12}{2} = 6 \) valid seating arrangements.
Final Answer: 6.
Let R = {(1, 2), (2, 3), (3, 3)}} be a relation defined on the set \( \{1, 2, 3, 4\} \). Then the minimum number of elements needed to be added in \( R \) so that \( R \) becomes an equivalence relation, is:


