Four men and three women can do a job in 6 days. When 5 men and 6 women work on the same job, the work gets completed in 4 days. How long will 2 women and 3 men take to do the job?
To solve the problem, let's first define the rates at which men and women work. Let the work done by one man in one day be m and the work done by one woman in one day be w.
According to the problem:
Four men and three women complete the job in 6 days. We can express this as: \(6(4m + 3w) = 1\).
Five men and six women complete the job in 4 days: \(4(5m + 6w) = 1\).
We now have two equations:
\(24m + 18w = 1\)
\(20m + 24w = 1\)
Let's solve these equations to find m and w.
Rearranging the first equation:
\(24m + 18w = 1\)
\(4m + 3w = \frac{1}{6}\)
Rearranging the second equation:
\(20m + 24w = 1\)
\(5m + 6w = \frac{1}{4}\)
Now multiply the first equation by 2 and the second by 1, to eliminate a variable: