To determine the correct order of adsorption of the gases A, B, C, and D on a fixed amount of charcoal based on their critical temperatures, we can follow these steps:
1. Understand the Concept of Critical Temperature:
- The critical temperature of a gas is the temperature above which it cannot be liquefied, regardless of the pressure applied. It is a measure of the intermolecular forces in the gas; higher critical temperatures indicate stronger intermolecular forces.
2. Identify the Given Critical Temperatures:
- Gas A: 5.3 K
- Gas B: 33.2 K
- Gas C: 126.0 K
- Gas D: 154.3 K
3. Relate Critical Temperature to Adsorption:
- Adsorption on a solid surface (like charcoal) is generally directly proportional to the critical temperature of the gas. This means that gases with higher critical temperatures will adsorb more strongly than those with lower critical temperatures.
4. Rank the Gases by Critical Temperature:
- From the highest to the lowest critical temperature:
- D (154.3 K)
- C (126.0 K)
- B (33.2 K)
- A (5.3 K)
5. Determine the Order of Adsorption:
- Since adsorption increases with increasing critical temperature, the order of adsorption for the gases on charcoal will be:
- D > C > B > A
6. Final Answer:
- The correct order of adsorption is: D, C, B, A.
Variation of solubility with temperature \(T\) for a gas in liquid is shown by the following graphs. The correct representation is
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is: