(A) It does not have alpha-hydrogen atom
(B) It has alpha-hydrogen atom
The Cannizzaro reaction is a disproportionation reaction of aldehydes that lack α-hydrogen atoms. In this reaction, two molecules of an aldehyde react in the presence of a strong base to produce a primary alcohol and a carboxylic acid.
Let's analyze each statement:
(A) It does not have alpha-hydrogen atom.: This is correct. Formaldehyde lacks α-hydrogen atoms, which is a requirement for the Cannizzaro reaction.
(B) It has alpha-hydrogen atom.: Formaldehyde (HCHO) does not have any α-hydrogen atoms. The α-carbon is the carbonyl carbon itself, which is directly bonded to hydrogen atoms.
(C) It does not undergo self-oxidation and reduction on heating with concentrated alkali.: This is incorrect. The Cannizzaro reaction involves self-oxidation and reduction.
(D) It undergoes self-oxidation and reduction on heating with concentrated alkali.: This is correct. The Cannizzaro reaction is a disproportionation reaction, which involves self-oxidation and reduction.
Since the Cannizzaro reaction occurs specifically for aldehydes without α-hydrogen atoms, and it involves self-oxidation and reduction, the correct reasons are (A) and (D).
However, the most direct reason why Formaldehyde undergoes the Cannizzaro reaction is because it lacks an alpha hydrogen.
Therefore, the most appropriate answer is:
Option 1: (A) It does not have an alpha-hydrogen atom
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Acidified KMnO_4 oxidizes sulphite to:
Which element is a strong reducing agent in +2 oxidation state and why?
Propanoic acid to Ethane